Matematika

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  • Penyelesaian:

    7. [tex]( \frac{4a^-4}{b^2})^-1/2[/tex]
    = [tex]( \frac{2^2 . a^-4}{b^2})^-1/2 [/tex]
    = [tex] \frac{2^-1 . a^2}{b^-1} [/tex]
    = 1/2(a²b)  (D).

    8. ([tex] \frac{8p^-9 . q^-2}{64p^-6 . q})^-1 [/tex]
    = ([tex] \frac{p^-9 q^-2}{8p^-6 . q})^-1 [/tex]
    = ([tex] \frac{p^-3 . q^-3}{8})^-1 [/tex]
    = ([tex] \frac{1}{2^3 . p^3 . q^3})^-1 [/tex]
    = 2pq^-3  (E).