tent hasil integral dari ∫ (x+3) (x-1) dx

Materi : Integral
Bahasan : Integral Tak Tentu
Jawaban : [tex]\frac{1}{3}x^{3} + x^{2} - 3 + C [/tex]

Langkah - langkah :
(x + 3) (x - 1) =
x² - x + 3x - 3
x² + 2x - 3

[tex] \int\limits {( x^{2} + 2x - 3)} \, dx \\ \\ = \frac{x^{2+1} }{2 + 1} + \frac{2x^{1+1} }{1+1} - 3 + C \\ \\ = \frac{x^{3}}{3} + \frac{2x^2}{2} -3 + C \\ \\ = \frac{1}{3}x^{3} + x^{2} - 3 + C [/tex]