tentukan f(x) jika kurva melalui titik (x,y) dari dy/dx = 3x (2-x) melalui titik (2,5)

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f(x) = y = ∫ dy/dx = ∫(3x)(2-x) dx = ∫ (6x - 3x²) dx
y = 3x² - x³ + c
(x,y) = (2,5)
5 = 3(2)² - (2)³ + c
5 = 12 -8 +c
5 = 4 + c
c = 1
y = f(x)= 3x² - x³ + 1