jumlah 10 suku pertama dari deret geometri 16-8+4-2+......adalah...... bsrta crnya

a = 16
r = - 8/16
= - 1/2

S10 = 10(1 - (-1/2)^10)) / (1 - (-1/2))
= 10((2^10 + 1)/2^10) / (3/2)
= (20/3)((2^10 + 1)/2^10)