selesaikan persamaan di bawah ini 1. 10y+2= -13 2. 15 p -5= -2 3.5(y+5)=-2 4.6(p+5)=-3(2p-1) 5.15×=2 - 3 pliss bantu jawab pr bsok
Matematika
wila13
Pertanyaan
selesaikan persamaan di bawah ini
1. 10y+2= -13
2. 15 p -5= -2
3.5(y+5)=-2
4.6(p+5)=-3(2p-1)
5.15×=2
-
3
pliss bantu jawab pr bsok
1. 10y+2= -13
2. 15 p -5= -2
3.5(y+5)=-2
4.6(p+5)=-3(2p-1)
5.15×=2
-
3
pliss bantu jawab pr bsok
1 Jawaban
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1. Jawaban BSunShine
1. 10y + 2 = -13
=> 10y = -13 - 2
=> y = -15/10
=> y = -1,5
2. 15p - 5 = -2
=> 15p = -2 + 5
=> 15p = 3
=> p = 3/15
=> p = 0,2
3. 5(y+5) = -2
=> 5y + 25 = -2
=> 5y = -2 - 25
=> 5y = -27
=> y = -5,4
4. 6(p+5) = -3(2p-1)
=> 6p + 30 = -6p + 3
=> 6p + 6p = 3 - 30
=> 12 p = -27
=> p = -2,25
5. 15x = 2
=> x = 2/15
=> x = 0,13