Tentukan integral nya Ka

Integral Tak Tentu

gunakan rumus  ∫ a xⁿ dx  = a/(n+1) xⁿ+¹ + c

a. ∫ 2 x² dx  = 2/(2+1) x²⁺¹  + c  = 2/3 x³ + c
b. ∫- 6x⁵ dx = -6/(5+1) x⁵⁺¹ + c = -6/6 x⁶ + c = - x⁶ + c
c. ∫ x¹² dx = 1/(12+1) x¹²⁺¹ + c = 1/13 x¹³ + c
d. ∫ -10x³⁹ dx = -10/(39+1) x³⁹⁺¹ + c = 10/40 x⁴⁰ + c = 1/4 x⁴⁰
e. ∫- 4 x⁻⁵ dx =  -4/(-5+1) x⁻⁵⁺¹ + c = -4/-4 x⁻⁴ + c = x⁻⁴ + c
f. ∫ 20 x⁵ dx = 20/(5+1) x⁵⁺¹ + c = 20/6 x⁶ + c
g. ∫5/x⁶ dx = ∫ 5 x⁻⁶ dx = 5/(-6+1) x⁻⁶⁺¹ +c = 5/-5 x⁻⁵ + c
= - x⁻⁵  +c
= -1/(x⁵) + c

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