Temukan tiga bilangan ganjil berurutan yg jumblahnya 1000 12000 dan 5

A]
misal bilangan itu a , b dan c
maka urutannya :
a , 2 + a , 4 + a

a + 2 + a + 4 + a = 1000
3a + 6 = 1000
3a = 1000 - 6
3a = 994
a = 994/3
a = 331 1/3

bilangan I = a = 331 1/3
bilangan II = 2 + a = 2 + 331 1/3 = 333 1/3
bilangan III = 4 + a = 4 + 331 1/3 = 335 1/3


B]
a + 2 + a + 4 + a = 12000
3a + 6 = 12000
3a = 12000 - 6
3a = 11994
a = 11994/3
a = 3998 => [tidak terdefinisi karena genap bukan ganjil]

C]
a + 2 + a + 4 + a = 5
3a + 6 = 5
3a = 5 - 6
3a = -1
a = -1/3


bilangan I = a = -1/3
bilangan II = 2 + a = 2 + (-1/3) = 6/3 - 1/3 = 5/3
bilangan III = 4 + a = 4 + (-1/3) = 12/3 - 1/3 = 11/3