eliminasi dan substitusi dari A=2x+y+z=44000 B=x+2y+z=50000 D=x+y+2z=58000 E=2x+2y+2z=.......

A =
2x + y + z = 44000 | semua * 2
4x + 2y + 2z = 88000

A eliminasi ke B
4x + 2y + 2z = 88000
x + 2y + z = 50000

3x + z = 38000 (i)

B =
x + 2y + z = 50000 | semua * 2
2x + 4y + 2z = 100000

B eliminasi ke D
2x + 4y + 2z = 100000
x + y + 2z = 58000

x + 3y = 42000 (ii)

eliminasi ii ke i
3x + 9y = 126000
3x + z = 38000

9y - z = 88000

z = 9y - 88000

nilai z disubtitusi ke A

2x + y + 9y - 88000 = 44000
2x + 10y = 44000 + 88000
2x + 10y = 132000 | sederhanakan, semua /2

x + 5y = 66000
x = 66000 - 5y

nilai z disubtitusi ke B
x + 2y + 9y - 88000 = 50000
x + 11y = 138000
x = 138000 - 11y

x = x
66000 - 5y = 138000 - 11y
11y - 5y = 138000 - 66000
6y = 72000
y = 12000

x = 66000 - 5y
x = 66000 - 5(12000)
x = 6000

3x + z = 38000
z = 38000 - 3(6000)
z = 20000

2x + 2y + 2z = 2(x + y +z)
= 2(6000 + 12000 + 20000)
= 2 (38000) = 76000