Matematika

Pertanyaan

Hitunglah:
[tex]\displaystyle \left ( \sqrt{2}+1 \right )^6+\left ( \sqrt{2}-1 \right )^6[/tex]

2 Jawaban

  • (√2 + 1)^6 + (√2 - 1)^6 =
    (√2 + 1)(√2 + 1)(√2 + 1)(√2 + 1)(√2 + 1)(√2 + 1) + (√2 - 1)(√2 - 1)(√2 - 1)(√2 - 1)(√2 - 1)(√2 - 1) =
    (99 + 70√2) + (99 - 70√2) =
    (4 + 4√2 + 2 + 4√2 + 8 + 2√2 + 2 + 2√2 + 1 + 8 + 8√2 + 4 + 8√2 + 16 + 4√2 + 4√2 + 2 + 8√2 + 16 + 4√2 + 16 + 16√2 + 8 + 4√2 + 8 + 2√2) + (4 - 4√2 + 2 - 4√2 + 8 - 2√2 + 2 - 2√2 + 1 + 8 - 8√2 + 4 - 8√2 + 16 - 4√2 - 4√2 + 2 - 8√2 + 16 - 4√2 + 16 - 16√2 + 8 - 4√2 + 8 - 2√2 =

    99 + 70√2 + 99 - 70√2 =
    99 + 99 =
    198
  • Materi Bentuk Akar (Modifikasi)
    Gambar lampiran jawaban ShanedizzySukardi

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