kak tolong dikerjakan soal invers . GAMPANG soalnya.

f(x)= 2x-5 / 3x+1
y= 2x-5/3x+1
y(3x+1)=2x-5
3xy+y=2x-5
3xy-2x=-y-5
x(3y-2)=-y-5
x=(-y-5)/(3y-2) (ubah x»y, y»x)
y=-(x+5)/(3x-2)
f(x)~¹ = -(x+5)/(3x-2)