Matematika

Pertanyaan

pakai cara (16y^4-1):(2y-1)

2 Jawaban

  • Mapel : Matematika
    Kelas : VIII SMP
    Materi : Persamaan Kuadrat

    Pembahasan :
    (16y⁴ - 1)/(2y - 1)
    = (4y² + 1)(4y² - 1)/(2y - 1)
    = (4y² + 1)(2y + 1)(2y - 1)/(2y - 1)
    = (4y² + 1)(2y + 1)
    = 8x³ + 4x² + 2x + 1
  • (16y^4 - 1) : (2y - 1)
    = (4y^2 + 1)(4y^2 - 1) : (2y - 1)
    = (4y^2 + 1)(2y + 1)(2y - 1) : (2y - 1)
    = (4y^2 + 1)(2y + 1)
    = 8y^3 + 4y^2 + 2y + 1

    Atau
    ............... 8y^3 + 4y^2 + 2y + 1 ====> hasil
    ................____________
    (2y - 1) √(16y^4 - 1)
    ................ 16y^4 - 8y^3
    ................ ------------------ -
    ............................. 8y^3 - 1
    ............................. 8y^3 - 4y^2
    ............................. ----------------- -
    ........................................ 4y^2 - 1
    ........................................ 4y^2 - 2y
    ........................................ ------------- -
    ................................................... 2y - 1
    ................................................... 2y - 1
    ................................................... -------- -
    ................................................... 0

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